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122424113001233 is a prime number
BaseRepresentation
bin11011110101100000010101…
…110001000111001100010001
3121001110122000221001122011002
4123311200111301013030101
5112021244040412014413
61112212505555231345
734533564434545331
oct3365402561071421
9531418027048132
10122424113001233
113600a85822108a
12118927438a8555
13534070cb41b34
1422335043350c1
15e247eadde958
hex6f5815c47311

122424113001233 has 2 divisors, whose sum is σ = 122424113001234. Its totient is φ = 122424113001232.

The previous prime is 122424113001143. The next prime is 122424113001247. The reversal of 122424113001233 is 332100311424221.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70636343038849 + 51787769962384 = 8404543^2 + 7196372^2 .

It is a cyclic number.

It is not a de Polignac number, because 122424113001233 - 246 = 52055368823569 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 122424113001196 and 122424113001205.

It is not a weakly prime, because it can be changed into another prime (122424113801233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61212056500616 + 61212056500617.

It is an arithmetic number, because the mean of its divisors is an integer number (61212056500617).

Almost surely, 2122424113001233 is an apocalyptic number.

It is an amenable number.

122424113001233 is a deficient number, since it is larger than the sum of its proper divisors (1).

122424113001233 is an equidigital number, since it uses as much as digits as its factorization.

122424113001233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 122424113001233 its reverse (332100311424221), we get a palindrome (454524424425454).

The spelling of 122424113001233 in words is "one hundred twenty-two trillion, four hundred twenty-four billion, one hundred thirteen million, one thousand, two hundred thirty-three".