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12243003131 is a prime number
BaseRepresentation
bin10110110011011110…
…10110011011111011
31011121020100222222102
423121233112123323
5200033202100011
65342510014015
7612251544452
oct133157263373
934536328872
1012243003131
115212946507
1224581a730b
1312015c7568
14841dd5b99
154b9c7173b
hex2d9bd66fb

12243003131 has 2 divisors, whose sum is σ = 12243003132. Its totient is φ = 12243003130.

The previous prime is 12243003049. The next prime is 12243003133. The reversal of 12243003131 is 13130034221.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12243003131 is a prime.

It is a super-2 number, since 2×122430031312 (a number of 21 digits) contains 22 as substring.

Together with 12243003133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12243003133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6121501565 + 6121501566.

It is an arithmetic number, because the mean of its divisors is an integer number (6121501566).

Almost surely, 212243003131 is an apocalyptic number.

12243003131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12243003131 is an equidigital number, since it uses as much as digits as its factorization.

12243003131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 12243003131 its reverse (13130034221), we get a palindrome (25373037352).

The spelling of 12243003131 in words is "twelve billion, two hundred forty-three million, three thousand, one hundred thirty-one".