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12243125131231 is a prime number
BaseRepresentation
bin1011001000101001001100…
…0111111101011111011111
31121100102122102220102220111
42302022103013331133133
53101042410013144411
642012225233230451
72402352024355051
oct262122307753737
947312572812814
1012243125131231
1139a0309a60425
121458971a02427
136aa6a2378197
143047db3278d1
151637123db721
hexb22931fd7df

12243125131231 has 2 divisors, whose sum is σ = 12243125131232. Its totient is φ = 12243125131230.

The previous prime is 12243125131219. The next prime is 12243125131261. The reversal of 12243125131231 is 13213152134221.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12243125131231 - 241 = 10044101875679 is a prime.

It is a super-2 number, since 2×122431251312312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12243125131193 and 12243125131202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12243125131261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6121562565615 + 6121562565616.

It is an arithmetic number, because the mean of its divisors is an integer number (6121562565616).

Almost surely, 212243125131231 is an apocalyptic number.

12243125131231 is a deficient number, since it is larger than the sum of its proper divisors (1).

12243125131231 is an equidigital number, since it uses as much as digits as its factorization.

12243125131231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8640, while the sum is 31.

Adding to 12243125131231 its reverse (13213152134221), we get a palindrome (25456277265452).

The spelling of 12243125131231 in words is "twelve trillion, two hundred forty-three billion, one hundred twenty-five million, one hundred thirty-one thousand, two hundred thirty-one".