Base | Representation |
---|---|
bin | 1011001000101001001100… |
… | …0111111101011111011111 |
3 | 1121100102122102220102220111 |
4 | 2302022103013331133133 |
5 | 3101042410013144411 |
6 | 42012225233230451 |
7 | 2402352024355051 |
oct | 262122307753737 |
9 | 47312572812814 |
10 | 12243125131231 |
11 | 39a0309a60425 |
12 | 1458971a02427 |
13 | 6aa6a2378197 |
14 | 3047db3278d1 |
15 | 1637123db721 |
hex | b22931fd7df |
12243125131231 has 2 divisors, whose sum is σ = 12243125131232. Its totient is φ = 12243125131230.
The previous prime is 12243125131219. The next prime is 12243125131261. The reversal of 12243125131231 is 13213152134221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12243125131231 - 241 = 10044101875679 is a prime.
It is a super-2 number, since 2×122431251312312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12243125131193 and 12243125131202.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12243125131261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6121562565615 + 6121562565616.
It is an arithmetic number, because the mean of its divisors is an integer number (6121562565616).
Almost surely, 212243125131231 is an apocalyptic number.
12243125131231 is a deficient number, since it is larger than the sum of its proper divisors (1).
12243125131231 is an equidigital number, since it uses as much as digits as its factorization.
12243125131231 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8640, while the sum is 31.
Adding to 12243125131231 its reverse (13213152134221), we get a palindrome (25456277265452).
The spelling of 12243125131231 in words is "twelve trillion, two hundred forty-three billion, one hundred twenty-five million, one hundred thirty-one thousand, two hundred thirty-one".
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