Base | Representation |
---|---|
bin | 10001110100010001001… |
… | …100000100001111100110 |
3 | 11100001021100011022000202 |
4 | 101310101030010033212 |
5 | 130024434114231032 |
6 | 2334243244310502 |
7 | 154312430520161 |
oct | 21642114041746 |
9 | 4301240138022 |
10 | 1224354055142 |
11 | 432277a44199 |
12 | 179355842432 |
13 | 8b5c1059c1a |
14 | 4338aba8ad8 |
15 | 21cacd16d62 |
hex | 11d113043e6 |
1224354055142 has 4 divisors (see below), whose sum is σ = 1836531082716. Its totient is φ = 612177027570.
The previous prime is 1224354055139. The next prime is 1224354055157. The reversal of 1224354055142 is 2415504534221.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 1224354055096 and 1224354055105.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 306088513784 + ... + 306088513787.
It is an arithmetic number, because the mean of its divisors is an integer number (459132770679).
Almost surely, 21224354055142 is an apocalyptic number.
1224354055142 is a deficient number, since it is larger than the sum of its proper divisors (612177027574).
1224354055142 is an equidigital number, since it uses as much as digits as its factorization.
1224354055142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 612177027573.
The product of its (nonzero) digits is 192000, while the sum is 38.
Adding to 1224354055142 its reverse (2415504534221), we get a palindrome (3639858589363).
The spelling of 1224354055142 in words is "one trillion, two hundred twenty-four billion, three hundred fifty-four million, fifty-five thousand, one hundred forty-two".
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