Base | Representation |
---|---|
bin | 111001000001000000… |
… | …1001101101000011011 |
3 | 102201001002021211021222 |
4 | 1302002001031220123 |
5 | 4001224223042342 |
6 | 132125351322255 |
7 | 11563121366561 |
oct | 1620201155033 |
9 | 381032254258 |
10 | 122440440347 |
11 | 47a21489075 |
12 | 1b89108038b |
13 | b713992104 |
14 | 5cd74d1a31 |
15 | 32b9368ed2 |
hex | 1c8204da1b |
122440440347 has 2 divisors, whose sum is σ = 122440440348. Its totient is φ = 122440440346.
The previous prime is 122440440337. The next prime is 122440440349. The reversal of 122440440347 is 743044044221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122440440347 - 210 = 122440439323 is a prime.
It is a super-2 number, since 2×1224404403472 (a number of 23 digits) contains 22 as substring.
Together with 122440440349, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (122440440349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61220220173 + 61220220174.
It is an arithmetic number, because the mean of its divisors is an integer number (61220220174).
Almost surely, 2122440440347 is an apocalyptic number.
122440440347 is a deficient number, since it is larger than the sum of its proper divisors (1).
122440440347 is an equidigital number, since it uses as much as digits as its factorization.
122440440347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86016, while the sum is 35.
Adding to 122440440347 its reverse (743044044221), we get a palindrome (865484484568).
The spelling of 122440440347 in words is "one hundred twenty-two billion, four hundred forty million, four hundred forty thousand, three hundred forty-seven".
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