12244331313540 has 72 divisors (see below), whose sum is σ = 37147287760128. Its totient is φ = 3264614406720.

The previous prime is 12244331313479. The next prime is 12244331313569. The reversal of 12244331313540 is 4531313344221.

12244331313540 is a `hidden beast` number, since 1 + 2 + 2 + 4 + 4 + 331 + 313 + 5 + 4 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 12244331313495 and 12244331313504.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4540596 + ... + 6716075.

It is an arithmetic number, because the mean of its divisors is an integer number (515934552224).

Almost surely, 2^{12244331313540} is an apocalyptic number.

12244331313540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12244331313540 is an abundant number, since it is smaller than the sum of its proper divisors (24902956446588).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12244331313540 is a wasteful number, since it uses less digits than its factorization.

12244331313540 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11262729 (or 11262724 counting only the distinct ones).

The product of its (nonzero) digits is 103680, while the sum is 36.

Adding to 12244331313540 its reverse (4531313344221), we get a palindrome (16775644657761).

The spelling of 12244331313540 in words is "twelve trillion, two hundred forty-four billion, three hundred thirty-one million, three hundred thirteen thousand, five hundred forty".