Base | Representation |
---|---|
bin | 1011001000101101111101… |
… | …0111001110011100100011 |
3 | 1121100112221120200221010012 |
4 | 2302023133113032130203 |
5 | 3101103014433420001 |
6 | 42013000204155135 |
7 | 2402425515314135 |
oct | 262133727163443 |
9 | 47315846627105 |
10 | 12244404201251 |
11 | 39a0905a62692 |
12 | 145906a238aab |
13 | 6aa847365651 |
14 | 3048bd15b055 |
15 | 1637898452bb |
hex | b22df5ce723 |
12244404201251 has 2 divisors, whose sum is σ = 12244404201252. Its totient is φ = 12244404201250.
The previous prime is 12244404201233. The next prime is 12244404201257. The reversal of 12244404201251 is 15210240444221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12244404201251 - 218 = 12244403939107 is a prime.
It is a super-2 number, since 2×122444042012512 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12244404201257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6122202100625 + 6122202100626.
It is an arithmetic number, because the mean of its divisors is an integer number (6122202100626).
Almost surely, 212244404201251 is an apocalyptic number.
12244404201251 is a deficient number, since it is larger than the sum of its proper divisors (1).
12244404201251 is an equidigital number, since it uses as much as digits as its factorization.
12244404201251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20480, while the sum is 32.
Adding to 12244404201251 its reverse (15210240444221), we get a palindrome (27454644645472).
The spelling of 12244404201251 in words is "twelve trillion, two hundred forty-four billion, four hundred four million, two hundred one thousand, two hundred fifty-one".
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