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12244703 is a prime number
BaseRepresentation
bin101110101101…
…011011011111
3212001002120112
4232231123133
511113312303
61114240235
7206035562
oct56553337
925032515
1012244703
116a03699
12412607b
1326c94b3
1418aa4d9
15111d0d8
hexbad6df

12244703 has 2 divisors, whose sum is σ = 12244704. Its totient is φ = 12244702.

The previous prime is 12244681. The next prime is 12244711. The reversal of 12244703 is 30744221.

12244703 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (30744221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12244703 - 212 = 12240607 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12244753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6122351 + 6122352.

It is an arithmetic number, because the mean of its divisors is an integer number (6122352).

Almost surely, 212244703 is an apocalyptic number.

12244703 is a deficient number, since it is larger than the sum of its proper divisors (1).

12244703 is an equidigital number, since it uses as much as digits as its factorization.

12244703 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 23.

The square root of 12244703 is about 3499.2432038942. The cubic root of 12244703 is about 230.4885833078.

Adding to 12244703 its reverse (30744221), we get a palindrome (42988924).

The spelling of 12244703 in words is "twelve million, two hundred forty-four thousand, seven hundred three".