Base | Representation |
---|---|
bin | 10001110100011010000… |
… | …110010100010110111111 |
3 | 11100001122202110002010122 |
4 | 101310122012110112333 |
5 | 130030240401340411 |
6 | 2334310144325155 |
7 | 154316224245413 |
oct | 21643206242677 |
9 | 4301582402118 |
10 | 1224503543231 |
11 | 432344366871 |
12 | 1793979137bb |
13 | 8b616009b07 |
14 | 433a299cd43 |
15 | 21cbaee49db |
hex | 11d1a1945bf |
1224503543231 has 2 divisors, whose sum is σ = 1224503543232. Its totient is φ = 1224503543230.
The previous prime is 1224503543149. The next prime is 1224503543243. The reversal of 1224503543231 is 1323453054221.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1224503543231 is a prime.
It is a super-2 number, since 2×12245035432312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1224503543191 and 1224503543200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1224503543261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612251771615 + 612251771616.
It is an arithmetic number, because the mean of its divisors is an integer number (612251771616).
Almost surely, 21224503543231 is an apocalyptic number.
1224503543231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1224503543231 is an equidigital number, since it uses as much as digits as its factorization.
1224503543231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 1224503543231 its reverse (1323453054221), we get a palindrome (2547956597452).
The spelling of 1224503543231 in words is "one trillion, two hundred twenty-four billion, five hundred three million, five hundred forty-three thousand, two hundred thirty-one".
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