Base | Representation |
---|---|
bin | 111001000001011100… |
… | …0110011101011110101 |
3 | 102201002002201020202211 |
4 | 1302002320303223311 |
5 | 4001241440423013 |
6 | 132131031533421 |
7 | 11563356306004 |
oct | 1620270635365 |
9 | 381062636684 |
10 | 122455014133 |
11 | 47a29732621 |
12 | 1b895b2a271 |
13 | b7169c575a |
14 | 5cd9406c3b |
15 | 32ba79723d |
hex | 1c82e33af5 |
122455014133 has 2 divisors, whose sum is σ = 122455014134. Its totient is φ = 122455014132.
The previous prime is 122455014119. The next prime is 122455014257. The reversal of 122455014133 is 331410554221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 118720215364 + 3734798769 = 344558^2 + 61113^2 .
It is a cyclic number.
It is not a de Polignac number, because 122455014133 - 213 = 122455005941 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 122455014095 and 122455014104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122455054133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61227507066 + 61227507067.
It is an arithmetic number, because the mean of its divisors is an integer number (61227507067).
Almost surely, 2122455014133 is an apocalyptic number.
It is an amenable number.
122455014133 is a deficient number, since it is larger than the sum of its proper divisors (1).
122455014133 is an equidigital number, since it uses as much as digits as its factorization.
122455014133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 122455014133 its reverse (331410554221), we get a palindrome (453865568354).
The spelling of 122455014133 in words is "one hundred twenty-two billion, four hundred fifty-five million, fourteen thousand, one hundred thirty-three".
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