Base | Representation |
---|---|
bin | 10001110101001001111… |
… | …001101100010101111011 |
3 | 11100010201122112201211022 |
4 | 101311021321230111323 |
5 | 130033411204234323 |
6 | 2334521514053055 |
7 | 154345133146331 |
oct | 21651171542573 |
9 | 4303648481738 |
10 | 1225305539963 |
11 | 43271604088a |
12 | 17958041a18b |
13 | 8b71320b7ab |
14 | 4343b2c7b51 |
15 | 21d166134c8 |
hex | 11d49e6c57b |
1225305539963 has 2 divisors, whose sum is σ = 1225305539964. Its totient is φ = 1225305539962.
The previous prime is 1225305539951. The next prime is 1225305540001. The reversal of 1225305539963 is 3699355035221.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1225305539963 is a prime.
It is a super-3 number, since 3×12253055399633 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1225305599963) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612652769981 + 612652769982.
It is an arithmetic number, because the mean of its divisors is an integer number (612652769982).
Almost surely, 21225305539963 is an apocalyptic number.
1225305539963 is a deficient number, since it is larger than the sum of its proper divisors (1).
1225305539963 is an equidigital number, since it uses as much as digits as its factorization.
1225305539963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6561000, while the sum is 53.
The spelling of 1225305539963 in words is "one trillion, two hundred twenty-five billion, three hundred five million, five hundred thirty-nine thousand, nine hundred sixty-three".
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