Base | Representation |
---|---|
bin | 10110110100101100… |
… | …00010010101110001 |
3 | 1011121221110020020012 |
4 | 23122112002111301 |
5 | 200043301110213 |
6 | 5343511224305 |
7 | 612434003105 |
oct | 133226022561 |
9 | 34557406205 |
10 | 12253144433 |
11 | 5218642852 |
12 | 245b678095 |
13 | 120373852a |
14 | 8434b5905 |
15 | 4baac64a8 |
hex | 2da582571 |
12253144433 has 2 divisors, whose sum is σ = 12253144434. Its totient is φ = 12253144432.
The previous prime is 12253144411. The next prime is 12253144439. The reversal of 12253144433 is 33444135221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11978645809 + 274498624 = 109447^2 + 16568^2 .
It is a cyclic number.
It is not a de Polignac number, because 12253144433 - 214 = 12253128049 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12253144433.
It is not a weakly prime, because it can be changed into another prime (12253144439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6126572216 + 6126572217.
It is an arithmetic number, because the mean of its divisors is an integer number (6126572217).
Almost surely, 212253144433 is an apocalyptic number.
It is an amenable number.
12253144433 is a deficient number, since it is larger than the sum of its proper divisors (1).
12253144433 is an equidigital number, since it uses as much as digits as its factorization.
12253144433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 34560, while the sum is 32.
Adding to 12253144433 its reverse (33444135221), we get a palindrome (45697279654).
The spelling of 12253144433 in words is "twelve billion, two hundred fifty-three million, one hundred forty-four thousand, four hundred thirty-three".
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