Base | Representation |
---|---|
bin | 10110110100101110… |
… | …00100000111101111 |
3 | 1011121221221220211101 |
4 | 23122113010013233 |
5 | 200043333220441 |
6 | 5343521103531 |
7 | 612436204456 |
oct | 133227040757 |
9 | 34557856741 |
10 | 12253413871 |
11 | 5218807226 |
12 | 245b787ba7 |
13 | 120380106a |
14 | 843545b9d |
15 | 4bab2b231 |
hex | 2da5c41ef |
12253413871 has 2 divisors, whose sum is σ = 12253413872. Its totient is φ = 12253413870.
The previous prime is 12253413769. The next prime is 12253413889. The reversal of 12253413871 is 17831435221.
It is a strong prime.
It is an emirp because it is prime and its reverse (17831435221) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12253413871 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12253413871.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12253413371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6126706935 + 6126706936.
It is an arithmetic number, because the mean of its divisors is an integer number (6126706936).
Almost surely, 212253413871 is an apocalyptic number.
12253413871 is a deficient number, since it is larger than the sum of its proper divisors (1).
12253413871 is an equidigital number, since it uses as much as digits as its factorization.
12253413871 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 40320, while the sum is 37.
The spelling of 12253413871 in words is "twelve billion, two hundred fifty-three million, four hundred thirteen thousand, eight hundred seventy-one".
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