Base | Representation |
---|---|
bin | 10001110101001100001… |
… | …010001000100110101001 |
3 | 11100010211021210110010222 |
4 | 101311030022020212221 |
5 | 130034000402420312 |
6 | 2334525345415425 |
7 | 154346103041414 |
oct | 21651412104651 |
9 | 4303737713128 |
10 | 1225343404457 |
11 | 432735452a57 |
12 | 17959103a575 |
13 | 8b71b008313 |
14 | 43442342b7b |
15 | 21d19ae2672 |
hex | 11d4c2889a9 |
1225343404457 has 2 divisors, whose sum is σ = 1225343404458. Its totient is φ = 1225343404456.
The previous prime is 1225343404429. The next prime is 1225343404463. The reversal of 1225343404457 is 7544043435221.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 667131201961 + 558212202496 = 816781^2 + 747136^2 .
It is a cyclic number.
It is not a de Polignac number, because 1225343404457 - 222 = 1225339210153 is a prime.
It is not a weakly prime, because it can be changed into another prime (1225343404427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612671702228 + 612671702229.
It is an arithmetic number, because the mean of its divisors is an integer number (612671702229).
Almost surely, 21225343404457 is an apocalyptic number.
It is an amenable number.
1225343404457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1225343404457 is an equidigital number, since it uses as much as digits as its factorization.
1225343404457 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1612800, while the sum is 44.
Adding to 1225343404457 its reverse (7544043435221), we get a palindrome (8769386839678).
The spelling of 1225343404457 in words is "one trillion, two hundred twenty-five billion, three hundred forty-three million, four hundred four thousand, four hundred fifty-seven".
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