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122555231420407 is a prime number
BaseRepresentation
bin11011110111011010011101…
…000010001011111111110111
3121001221011110210111110110021
4123313122131002023333313
5112030421103220423112
61112353032430110011
734546215611662102
oct3367323502137767
9531834423443407
10122555231420407
1136060422146085
12118b403704b307
13534cba7646056
1422399c2175739
15e27e22026907
hex6f769d08bff7

122555231420407 has 2 divisors, whose sum is σ = 122555231420408. Its totient is φ = 122555231420406.

The previous prime is 122555231420399. The next prime is 122555231420579. The reversal of 122555231420407 is 704024132555221.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 122555231420407 - 23 = 122555231420399 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122555231420107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61277615710203 + 61277615710204.

It is an arithmetic number, because the mean of its divisors is an integer number (61277615710204).

Almost surely, 2122555231420407 is an apocalyptic number.

122555231420407 is a deficient number, since it is larger than the sum of its proper divisors (1).

122555231420407 is an equidigital number, since it uses as much as digits as its factorization.

122555231420407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 672000, while the sum is 43.

Adding to 122555231420407 its reverse (704024132555221), we get a palindrome (826579363975628).

The spelling of 122555231420407 in words is "one hundred twenty-two trillion, five hundred fifty-five billion, two hundred thirty-one million, four hundred twenty thousand, four hundred seven".