Base | Representation |
---|---|
bin | 10001110101100100101… |
… | …000111100001010010111 |
3 | 11100011212220122121222112 |
4 | 101311210220330022113 |
5 | 130040321024230033 |
6 | 2335034221021235 |
7 | 154362221136221 |
oct | 21654450741227 |
9 | 4304786577875 |
10 | 1225754133143 |
11 | 432926286551 |
12 | 1796866b481b |
13 | 8b785135047 |
14 | 43480adb411 |
15 | 21d40bc4c48 |
hex | 11d64a3c297 |
1225754133143 has 2 divisors, whose sum is σ = 1225754133144. Its totient is φ = 1225754133142.
The previous prime is 1225754133127. The next prime is 1225754133161. The reversal of 1225754133143 is 3413314575221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1225754133143 - 24 = 1225754133127 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1225754133143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1225754138143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612877066571 + 612877066572.
It is an arithmetic number, because the mean of its divisors is an integer number (612877066572).
Almost surely, 21225754133143 is an apocalyptic number.
1225754133143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1225754133143 is an equidigital number, since it uses as much as digits as its factorization.
1225754133143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 302400, while the sum is 41.
The spelling of 1225754133143 in words is "one trillion, two hundred twenty-five billion, seven hundred fifty-four million, one hundred thirty-three thousand, one hundred forty-three".
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