Base | Representation |
---|---|
bin | 11011111000001000001101… |
… | …101000000101100110101101 |
3 | 121002002212022000002011021021 |
4 | 123320020031220011212231 |
5 | 112032222214422403031 |
6 | 1112431400122134141 |
7 | 34552605313616401 |
oct | 3370101550054655 |
9 | 532085260064237 |
10 | 122604365044141 |
11 | 3607a245861892 |
12 | 11901669951351 |
13 | 5354707a628a6 |
14 | 223c1237bd101 |
15 | e2934a7d2511 |
hex | 6f820da059ad |
122604365044141 has 2 divisors, whose sum is σ = 122604365044142. Its totient is φ = 122604365044140.
The previous prime is 122604365044039. The next prime is 122604365044153. The reversal of 122604365044141 is 141440563406221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 89079222836041 + 33525142208100 = 9438179^2 + 5790090^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-122604365044141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (122604365044241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61302182522070 + 61302182522071.
It is an arithmetic number, because the mean of its divisors is an integer number (61302182522071).
Almost surely, 2122604365044141 is an apocalyptic number.
It is an amenable number.
122604365044141 is a deficient number, since it is larger than the sum of its proper divisors (1).
122604365044141 is an equidigital number, since it uses as much as digits as its factorization.
122604365044141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 552960, while the sum is 43.
The spelling of 122604365044141 in words is "one hundred twenty-two trillion, six hundred four billion, three hundred sixty-five million, forty-four thousand, one hundred forty-one".
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