Base | Representation |
---|---|
bin | 1011001001101111100000… |
… | …1111101001001011010011 |
3 | 1121102020100222010222221112 |
4 | 2302123320033221023103 |
5 | 3101400034341410141 |
6 | 42025030303443535 |
7 | 2403620554100414 |
oct | 262337017511323 |
9 | 47366328128845 |
10 | 12262001513171 |
11 | 39a8316203583 |
12 | 146055b5b65ab |
13 | 6ac3c0022c57 |
14 | 3056ac2c380b |
15 | 163e696a87eb |
hex | b26f83e92d3 |
12262001513171 has 2 divisors, whose sum is σ = 12262001513172. Its totient is φ = 12262001513170.
The previous prime is 12262001513131. The next prime is 12262001513183. The reversal of 12262001513171 is 17131510026221.
It is a strong prime.
It is an emirp because it is prime and its reverse (17131510026221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12262001513171 - 210 = 12262001512147 is a prime.
It is a super-2 number, since 2×122620015131712 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12262001513131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6131000756585 + 6131000756586.
It is an arithmetic number, because the mean of its divisors is an integer number (6131000756586).
Almost surely, 212262001513171 is an apocalyptic number.
12262001513171 is a deficient number, since it is larger than the sum of its proper divisors (1).
12262001513171 is an equidigital number, since it uses as much as digits as its factorization.
12262001513171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 32.
Adding to 12262001513171 its reverse (17131510026221), we get a palindrome (29393511539392).
The spelling of 12262001513171 in words is "twelve trillion, two hundred sixty-two billion, one million, five hundred thirteen thousand, one hundred seventy-one".
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