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122664521437 is a prime number
BaseRepresentation
bin111001000111101100…
…0000000111011011101
3102201121200221022202121
41302033120000323131
54002204104141222
6132203514222541
711601512141323
oct1621730007335
9381550838677
10122664521437
1148026a19557
121b934124a51
13b74b22b283
145d19181d13
1532cdd7d5c7
hex1c8f600edd

122664521437 has 2 divisors, whose sum is σ = 122664521438. Its totient is φ = 122664521436.

The previous prime is 122664521429. The next prime is 122664521443. The reversal of 122664521437 is 734125466221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108833350201 + 13831171236 = 329899^2 + 117606^2 .

It is a cyclic number.

It is not a de Polignac number, because 122664521437 - 23 = 122664521429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 122664521393 and 122664521402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (122664522437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61332260718 + 61332260719.

It is an arithmetic number, because the mean of its divisors is an integer number (61332260719).

Almost surely, 2122664521437 is an apocalyptic number.

It is an amenable number.

122664521437 is a deficient number, since it is larger than the sum of its proper divisors (1).

122664521437 is an equidigital number, since it uses as much as digits as its factorization.

122664521437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 483840, while the sum is 43.

Adding to 122664521437 its reverse (734125466221), we get a palindrome (856789987658).

The spelling of 122664521437 in words is "one hundred twenty-two billion, six hundred sixty-four million, five hundred twenty-one thousand, four hundred thirty-seven".