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12271814802713 is a prime number
BaseRepresentation
bin1011001010010100000100…
…1010010111110100011001
31121110011200212120202110202
42302211001022113310121
53102030134042141323
642033332140351545
72404416003505124
oct262450112276431
947404625522422
1012271814802713
113a014a1592224
121462439b455b5
136b02c512a05b
14305d5d7233bb
15164340e84d28
hexb2941297d19

12271814802713 has 2 divisors, whose sum is σ = 12271814802714. Its totient is φ = 12271814802712.

The previous prime is 12271814802607. The next prime is 12271814802721. The reversal of 12271814802713 is 31720841817221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12265033609609 + 6781193104 = 3502147^2 + 82348^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12271814802713 is a prime.

It is a super-4 number, since 4×122718148027134 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (12271814802743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6135907401356 + 6135907401357.

It is an arithmetic number, because the mean of its divisors is an integer number (6135907401357).

Almost surely, 212271814802713 is an apocalyptic number.

It is an amenable number.

12271814802713 is a deficient number, since it is larger than the sum of its proper divisors (1).

12271814802713 is an equidigital number, since it uses as much as digits as its factorization.

12271814802713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 301056, while the sum is 47.

The spelling of 12271814802713 in words is "twelve trillion, two hundred seventy-one billion, eight hundred fourteen million, eight hundred two thousand, seven hundred thirteen".