Base | Representation |
---|---|
bin | 10001110111101110001… |
… | …001100001010001001111 |
3 | 11100101211200201100100210 |
4 | 101313232021201101033 |
5 | 130110032123333320 |
6 | 2340055152253503 |
7 | 154503333363543 |
oct | 21675611412117 |
9 | 4311750640323 |
10 | 1228061152335 |
11 | 4338aa561186 |
12 | 17a00b241293 |
13 | 8ba62097064 |
14 | 4361d275a23 |
15 | 21e284d10e0 |
hex | 11dee26144f |
1228061152335 has 32 divisors (see below), whose sum is σ = 2105742481920. Its totient is φ = 609557021568.
The previous prime is 1228061152333. The next prime is 1228061152343. The reversal of 1228061152335 is 5332511608221.
It is not a de Polignac number, because 1228061152335 - 21 = 1228061152333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1228061152293 and 1228061152302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1228061152333) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 48089905 + ... + 48115434.
It is an arithmetic number, because the mean of its divisors is an integer number (65804452560).
Almost surely, 21228061152335 is an apocalyptic number.
1228061152335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1228061152335 is a deficient number, since it is larger than the sum of its proper divisors (877681329585).
1228061152335 is a wasteful number, since it uses less digits than its factorization.
1228061152335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96205407.
The product of its (nonzero) digits is 86400, while the sum is 39.
The spelling of 1228061152335 in words is "one trillion, two hundred twenty-eight billion, sixty-one million, one hundred fifty-two thousand, three hundred thirty-five".
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