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1228134489083 is a prime number
BaseRepresentation
bin10001110111110010100…
…001010001101111111011
311100102000210201020110122
4101313302201101233323
5130110204412122313
62340110332203455
7154505213625365
oct21676241215773
94312023636418
101228134489083
114339379a1167
1217a02b90958b
138ba74333598
1443628cc5d35
1521e2eb6a708
hex11df2851bfb

1228134489083 has 2 divisors, whose sum is σ = 1228134489084. Its totient is φ = 1228134489082.

The previous prime is 1228134489007. The next prime is 1228134489143. The reversal of 1228134489083 is 3809844318221.

It is a strong prime.

It is an emirp because it is prime and its reverse (3809844318221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1228134489083 - 212 = 1228134484987 is a prime.

It is a super-3 number, since 3×12281344890833 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1228134488083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 614067244541 + 614067244542.

It is an arithmetic number, because the mean of its divisors is an integer number (614067244542).

Almost surely, 21228134489083 is an apocalyptic number.

1228134489083 is a deficient number, since it is larger than the sum of its proper divisors (1).

1228134489083 is an equidigital number, since it uses as much as digits as its factorization.

1228134489083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2654208, while the sum is 53.

The spelling of 1228134489083 in words is "one trillion, two hundred twenty-eight billion, one hundred thirty-four million, four hundred eighty-nine thousand, eighty-three".