Base | Representation |
---|---|
bin | 10110111000000011… |
… | …10111011111001101 |
3 | 1011200220122100101211 |
4 | 23130001313133031 |
5 | 200123020132113 |
6 | 5350401134421 |
7 | 613226163346 |
oct | 133401673715 |
9 | 34626570354 |
10 | 12281411533 |
11 | 523259a296 |
12 | 246902a411 |
13 | 1209554821 |
14 | 8471530cd |
15 | 4bd30bb3d |
hex | 2dc0777cd |
12281411533 has 2 divisors, whose sum is σ = 12281411534. Its totient is φ = 12281411532.
The previous prime is 12281411447. The next prime is 12281411537. The reversal of 12281411533 is 33511418221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12055600804 + 225810729 = 109798^2 + 15027^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12281411533 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12281411495 and 12281411504.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12281411537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6140705766 + 6140705767.
It is an arithmetic number, because the mean of its divisors is an integer number (6140705767).
Almost surely, 212281411533 is an apocalyptic number.
It is an amenable number.
12281411533 is a deficient number, since it is larger than the sum of its proper divisors (1).
12281411533 is an equidigital number, since it uses as much as digits as its factorization.
12281411533 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5760, while the sum is 31.
Adding to 12281411533 its reverse (33511418221), we get a palindrome (45792829754).
The spelling of 12281411533 in words is "twelve billion, two hundred eighty-one million, four hundred eleven thousand, five hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.232 sec. • engine limits •