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12292365133 is a prime number
BaseRepresentation
bin10110111001010111…
…01001101101001101
31011201200020211220201
423130223221231031
5200133321141013
65351432013501
7613421244136
oct133453515515
934650224821
1012292365133
1152387a0954
122470831291
13120b8bb449
148487a4c8d
154be2723dd
hex2dcae9b4d

12292365133 has 2 divisors, whose sum is σ = 12292365134. Its totient is φ = 12292365132.

The previous prime is 12292365067. The next prime is 12292365139. The reversal of 12292365133 is 33156329221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6618961449 + 5673403684 = 81357^2 + 75322^2 .

It is a cyclic number.

It is not a de Polignac number, because 12292365133 - 221 = 12290267981 is a prime.

It is a super-2 number, since 2×122923651332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12292365092 and 12292365101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12292365139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6146182566 + 6146182567.

It is an arithmetic number, because the mean of its divisors is an integer number (6146182567).

Almost surely, 212292365133 is an apocalyptic number.

It is an amenable number.

12292365133 is a deficient number, since it is larger than the sum of its proper divisors (1).

12292365133 is an equidigital number, since it uses as much as digits as its factorization.

12292365133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 58320, while the sum is 37.

The spelling of 12292365133 in words is "twelve billion, two hundred ninety-two million, three hundred sixty-five thousand, one hundred thirty-three".