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123000304055093 is a prime number
BaseRepresentation
bin11011111101111000111101…
…011011100011001100110101
3121010111201021200011220120022
4123331320331123203030311
5112110214110314230333
61113333320513214525
734623323124650243
oct3375707533431465
9533451250156508
10123000304055093
1136212155033a93
1211966348b61445
135382b56c4731a
1422533644b3793
15e347c0909c98
hex6fde3d6e3335

123000304055093 has 2 divisors, whose sum is σ = 123000304055094. Its totient is φ = 123000304055092.

The previous prime is 123000304055081. The next prime is 123000304055129. The reversal of 123000304055093 is 390550403000321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92109184606609 + 30891119448484 = 9597353^2 + 5557978^2 .

It is an emirp because it is prime and its reverse (390550403000321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123000304055093 - 216 = 123000303989557 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123000304055593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61500152027546 + 61500152027547.

It is an arithmetic number, because the mean of its divisors is an integer number (61500152027547).

Almost surely, 2123000304055093 is an apocalyptic number.

It is an amenable number.

123000304055093 is a deficient number, since it is larger than the sum of its proper divisors (1).

123000304055093 is an equidigital number, since it uses as much as digits as its factorization.

123000304055093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48600, while the sum is 35.

The spelling of 123000304055093 in words is "one hundred twenty-three trillion, three hundred four million, fifty-five thousand, ninety-three".