Search a number
-
+
1230011212013 is a prime number
BaseRepresentation
bin10001111001100010011…
…000011010000011101101
311100120212121002122100022
4101321202120122003231
5130123030332241023
62341020453011525
7154602552536663
oct21714230320355
94316777078308
101230011212013
11434710298951
1217a474323ba5
138bcb30a721c
1443766250c33
1521ede7cb7c8
hex11e6261a0ed

1230011212013 has 2 divisors, whose sum is σ = 1230011212014. Its totient is φ = 1230011212012.

The previous prime is 1230011211997. The next prime is 1230011212061. The reversal of 1230011212013 is 3102121100321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1150013877769 + 79997334244 = 1072387^2 + 282838^2 .

It is a cyclic number.

It is not a de Polignac number, because 1230011212013 - 24 = 1230011211997 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1230011211982 and 1230011212000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1230011212093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615005606006 + 615005606007.

It is an arithmetic number, because the mean of its divisors is an integer number (615005606007).

Almost surely, 21230011212013 is an apocalyptic number.

It is an amenable number.

1230011212013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1230011212013 is an equidigital number, since it uses as much as digits as its factorization.

1230011212013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1230011212013 its reverse (3102121100321), we get a palindrome (4332132312334).

The spelling of 1230011212013 in words is "one trillion, two hundred thirty billion, eleven million, two hundred twelve thousand, thirteen".