Base | Representation |
---|---|
bin | 1011001011111101100011… |
… | …1000101111101001011010 |
3 | 1121112212210012212000211010 |
4 | 2302333120320233221122 |
5 | 3103011131302403310 |
6 | 42054333552114350 |
7 | 2406440455655301 |
oct | 262773070575132 |
9 | 47485705760733 |
10 | 12300130122330 |
11 | 3a12501876a16 |
12 | 1467a208359b6 |
13 | 6b2b8847a84b |
14 | 307488113438 |
15 | 164e4bc34320 |
hex | b2fd8e2fa5a |
12300130122330 has 16 divisors (see below), whose sum is σ = 29520312293664. Its totient is φ = 3280034699280.
The previous prime is 12300130122299. The next prime is 12300130122349. The reversal of 12300130122330 is 3322103100321.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 12300130122297 and 12300130122306.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 205002168676 + ... + 205002168735.
It is an arithmetic number, because the mean of its divisors is an integer number (1845019518354).
Almost surely, 212300130122330 is an apocalyptic number.
12300130122330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12300130122330 is an abundant number, since it is smaller than the sum of its proper divisors (17220182171334).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12300130122330 is a wasteful number, since it uses less digits than its factorization.
12300130122330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 410004337421.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 12300130122330 its reverse (3322103100321), we get a palindrome (15622233222651).
The spelling of 12300130122330 in words is "twelve trillion, three hundred billion, one hundred thirty million, one hundred twenty-two thousand, three hundred thirty".
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