Base | Representation |
---|---|
bin | 1011001011111101110110… |
… | …1110000100101100010011 |
3 | 1121112212222212102202121012 |
4 | 2302333131232010230103 |
5 | 3103011313032223102 |
6 | 42054350010121135 |
7 | 2406442462134425 |
oct | 262773556045423 |
9 | 47485885382535 |
10 | 12300211211027 |
11 | 3a12543621073 |
12 | 1467a43a201ab |
13 | 6b2b9c1cc61c |
14 | 307494bc0815 |
15 | 164e53e00752 |
hex | b2fddb84b13 |
12300211211027 has 2 divisors, whose sum is σ = 12300211211028. Its totient is φ = 12300211211026.
The previous prime is 12300211210981. The next prime is 12300211211047. The reversal of 12300211211027 is 72011211200321.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12300211211027 - 232 = 12295916243731 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12300211210993 and 12300211211011.
It is not a weakly prime, because it can be changed into another prime (12300211211047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6150105605513 + 6150105605514.
It is an arithmetic number, because the mean of its divisors is an integer number (6150105605514).
Almost surely, 212300211211027 is an apocalyptic number.
12300211211027 is a deficient number, since it is larger than the sum of its proper divisors (1).
12300211211027 is an equidigital number, since it uses as much as digits as its factorization.
12300211211027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 336, while the sum is 23.
Adding to 12300211211027 its reverse (72011211200321), we get a palindrome (84311422411348).
The spelling of 12300211211027 in words is "twelve trillion, three hundred billion, two hundred eleven million, two hundred eleven thousand, twenty-seven".
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