Base | Representation |
---|---|
bin | 111001010001110000… |
… | …1011111101100001011 |
3 | 102202111021000000012221 |
4 | 1302203201133230023 |
5 | 4003402123113201 |
6 | 132301231314511 |
7 | 11613055301362 |
oct | 1624341375413 |
9 | 382437000187 |
10 | 123002551051 |
11 | 4818a808176 |
12 | 1ba0937ba37 |
13 | b7a3282ab3 |
14 | 5d4c0147d9 |
15 | 32ed8a04a1 |
hex | 1ca385fb0b |
123002551051 has 2 divisors, whose sum is σ = 123002551052. Its totient is φ = 123002551050.
The previous prime is 123002551013. The next prime is 123002551079. The reversal of 123002551051 is 150155200321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123002551051 - 233 = 114412616459 is a prime.
It is a super-2 number, since 2×1230025510512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (123002551351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61501275525 + 61501275526.
It is an arithmetic number, because the mean of its divisors is an integer number (61501275526).
Almost surely, 2123002551051 is an apocalyptic number.
123002551051 is a deficient number, since it is larger than the sum of its proper divisors (1).
123002551051 is an equidigital number, since it uses as much as digits as its factorization.
123002551051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1500, while the sum is 25.
Adding to 123002551051 its reverse (150155200321), we get a palindrome (273157751372).
The spelling of 123002551051 in words is "one hundred twenty-three billion, two million, five hundred fifty-one thousand, fifty-one".
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