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123003402341201 is a prime number
BaseRepresentation
bin11011111101111011110110…
…000110100100101101010001
3121010112000021121011011002122
4123331323312012210231101
5112110241431444404301
61113334552152224025
734623462655646324
oct3375736606445521
9533460247134078
10123003402341201
11362134a4a25218
1211966a7269b015
13538322bac2205
142253579b827bb
15e3490291581b
hex6fdef61a4b51

123003402341201 has 2 divisors, whose sum is σ = 123003402341202. Its totient is φ = 123003402341200.

The previous prime is 123003402341161. The next prime is 123003402341203. The reversal of 123003402341201 is 102143204300321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 67572756670225 + 55430645670976 = 8220265^2 + 7445176^2 .

It is an emirp because it is prime and its reverse (102143204300321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 123003402341201 - 218 = 123003402079057 is a prime.

It is a super-2 number, since 2×1230034023412012 (a number of 29 digits) contains 22 as substring.

Together with 123003402341203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (123003402341203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61501701170600 + 61501701170601.

It is an arithmetic number, because the mean of its divisors is an integer number (61501701170601).

Almost surely, 2123003402341201 is an apocalyptic number.

It is an amenable number.

123003402341201 is a deficient number, since it is larger than the sum of its proper divisors (1).

123003402341201 is an equidigital number, since it uses as much as digits as its factorization.

123003402341201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 123003402341201 its reverse (102143204300321), we get a palindrome (225146606641522).

It can be divided in two parts, 123003 and 402341201, that added together give a palindrome (402464204).

The spelling of 123003402341201 in words is "one hundred twenty-three trillion, three billion, four hundred two million, three hundred forty-one thousand, two hundred one".