Base | Representation |
---|---|
bin | 11011111101111011110110… |
… | …000110100100101101010001 |
3 | 121010112000021121011011002122 |
4 | 123331323312012210231101 |
5 | 112110241431444404301 |
6 | 1113334552152224025 |
7 | 34623462655646324 |
oct | 3375736606445521 |
9 | 533460247134078 |
10 | 123003402341201 |
11 | 362134a4a25218 |
12 | 11966a7269b015 |
13 | 538322bac2205 |
14 | 2253579b827bb |
15 | e3490291581b |
hex | 6fdef61a4b51 |
123003402341201 has 2 divisors, whose sum is σ = 123003402341202. Its totient is φ = 123003402341200.
The previous prime is 123003402341161. The next prime is 123003402341203. The reversal of 123003402341201 is 102143204300321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67572756670225 + 55430645670976 = 8220265^2 + 7445176^2 .
It is an emirp because it is prime and its reverse (102143204300321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 123003402341201 - 218 = 123003402079057 is a prime.
It is a super-2 number, since 2×1230034023412012 (a number of 29 digits) contains 22 as substring.
Together with 123003402341203, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (123003402341203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61501701170600 + 61501701170601.
It is an arithmetic number, because the mean of its divisors is an integer number (61501701170601).
Almost surely, 2123003402341201 is an apocalyptic number.
It is an amenable number.
123003402341201 is a deficient number, since it is larger than the sum of its proper divisors (1).
123003402341201 is an equidigital number, since it uses as much as digits as its factorization.
123003402341201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 123003402341201 its reverse (102143204300321), we get a palindrome (225146606641522).
It can be divided in two parts, 123003 and 402341201, that added together give a palindrome (402464204).
The spelling of 123003402341201 in words is "one hundred twenty-three trillion, three billion, four hundred two million, three hundred forty-one thousand, two hundred one".
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