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1230044330131 is a prime number
BaseRepresentation
bin10001111001100100010…
…110101111100010010011
311100120221220102012212021
4101321210112233202103
5130123112322031011
62341024034512311
7154603434203161
oct21714426574223
94316856365767
101230044330131
11434727a58aa1
1217a483435697
138bcb9c01546
144376a7d2231
1521ee266e471
hex11e645af893

1230044330131 has 2 divisors, whose sum is σ = 1230044330132. Its totient is φ = 1230044330130.

The previous prime is 1230044330107. The next prime is 1230044330173. The reversal of 1230044330131 is 1310334400321.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1230044330131 is a prime.

It is a super-2 number, since 2×12300443301312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1230044330096 and 1230044330105.

It is not a weakly prime, because it can be changed into another prime (1230044330101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615022165065 + 615022165066.

It is an arithmetic number, because the mean of its divisors is an integer number (615022165066).

Almost surely, 21230044330131 is an apocalyptic number.

1230044330131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1230044330131 is an equidigital number, since it uses as much as digits as its factorization.

1230044330131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1230044330131 its reverse (1310334400321), we get a palindrome (2540378730452).

The spelling of 1230044330131 in words is "one trillion, two hundred thirty billion, forty-four million, three hundred thirty thousand, one hundred thirty-one".