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123010232230019 is a prime number
BaseRepresentation
bin11011111110000010001101…
…001100100010000010000011
3121010112122220120210110012202
4123332002031030202002003
5112110344423422330034
61113342042012343415
734624124141024531
oct3376021514420203
9533478816713182
10123010232230019
113621638a250832
1211968259a74b6b
135383a79aa7344
142253a26c9b151
15e34ba232b47e
hex6fe08d322083

123010232230019 has 2 divisors, whose sum is σ = 123010232230020. Its totient is φ = 123010232230018.

The previous prime is 123010232230007. The next prime is 123010232230021. The reversal of 123010232230019 is 910032232010321.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123010232230019 is a prime.

It is a super-2 number, since 2×1230102322300192 (a number of 29 digits) contains 22 as substring.

Together with 123010232230021, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 123010232229973 and 123010232230000.

It is not a weakly prime, because it can be changed into another prime (123010232200019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61505116115009 + 61505116115010.

It is an arithmetic number, because the mean of its divisors is an integer number (61505116115010).

Almost surely, 2123010232230019 is an apocalyptic number.

123010232230019 is a deficient number, since it is larger than the sum of its proper divisors (1).

123010232230019 is an equidigital number, since it uses as much as digits as its factorization.

123010232230019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 29.

The spelling of 123010232230019 in words is "one hundred twenty-three trillion, ten billion, two hundred thirty-two million, two hundred thirty thousand, nineteen".