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12301132013 is a prime number
BaseRepresentation
bin10110111010011010…
…00110000011101101
31011202021202020210222
423131031012003231
5200143042211023
65352343541125
7613555616432
oct133515060355
934667666728
1012301132013
115242739605
12247375a7a5
13121066a951
14849a07b89
154bee04cc8
hex2dd3460ed

12301132013 has 2 divisors, whose sum is σ = 12301132014. Its totient is φ = 12301132012.

The previous prime is 12301132009. The next prime is 12301132033. The reversal of 12301132013 is 31023110321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12254932804 + 46199209 = 110702^2 + 6797^2 .

It is a cyclic number.

It is not a de Polignac number, because 12301132013 - 22 = 12301132009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12301131982 and 12301132000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12301132033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6150566006 + 6150566007.

It is an arithmetic number, because the mean of its divisors is an integer number (6150566007).

Almost surely, 212301132013 is an apocalyptic number.

It is an amenable number.

12301132013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12301132013 is an equidigital number, since it uses as much as digits as its factorization.

12301132013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 12301132013 its reverse (31023110321), we get a palindrome (43324242334).

The spelling of 12301132013 in words is "twelve billion, three hundred one million, one hundred thirty-two thousand, thirteen".