Base | Representation |
---|---|
bin | 10001111001101000011… |
… | …101011110010010000011 |
3 | 11100121010201000100010112 |
4 | 101321220131132102003 |
5 | 130123232440001311 |
6 | 2341034535021535 |
7 | 154605231464525 |
oct | 21715035362203 |
9 | 4317121010115 |
10 | 1230113203331 |
11 | 43476291a4a1 |
12 | 17a4a250a8ab |
13 | 8bccb26720c |
14 | 437759dda15 |
15 | 21ee872628b |
hex | 11e6875e483 |
1230113203331 has 2 divisors, whose sum is σ = 1230113203332. Its totient is φ = 1230113203330.
The previous prime is 1230113203321. The next prime is 1230113203351. The reversal of 1230113203331 is 1333023110321.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1230113203331 is a prime.
It is a super-2 number, since 2×12301132033312 (a number of 25 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 1230113203297 and 1230113203306.
It is not a weakly prime, because it can be changed into another prime (1230113203321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615056601665 + 615056601666.
It is an arithmetic number, because the mean of its divisors is an integer number (615056601666).
Almost surely, 21230113203331 is an apocalyptic number.
1230113203331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1230113203331 is an equidigital number, since it uses as much as digits as its factorization.
1230113203331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 1230113203331 its reverse (1333023110321), we get a palindrome (2563136313652).
The spelling of 1230113203331 in words is "one trillion, two hundred thirty billion, one hundred thirteen million, two hundred three thousand, three hundred thirty-one".
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