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123013203023537 is a prime number
BaseRepresentation
bin11011111110000100111110…
…010001001101011010110001
3121010112221120121212101210022
4123332010332101031122301
5112110422014433223122
61113343252455013225
734624260563245241
oct3376047621153261
9533487517771708
10123013203023537
1136217674182992
121196894896a215
135384131403b28
142253c2965db21
15e34cc8051642
hex6fe13e44d6b1

123013203023537 has 2 divisors, whose sum is σ = 123013203023538. Its totient is φ = 123013203023536.

The previous prime is 123013203023533. The next prime is 123013203023617. The reversal of 123013203023537 is 735320302310321.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 81298642763776 + 41714560259761 = 9016576^2 + 6458681^2 .

It is a cyclic number.

It is not a de Polignac number, because 123013203023537 - 22 = 123013203023533 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 123013203023497 and 123013203023506.

It is not a weakly prime, because it can be changed into another prime (123013203023533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61506601511768 + 61506601511769.

It is an arithmetic number, because the mean of its divisors is an integer number (61506601511769).

Almost surely, 2123013203023537 is an apocalyptic number.

It is an amenable number.

123013203023537 is a deficient number, since it is larger than the sum of its proper divisors (1).

123013203023537 is an equidigital number, since it uses as much as digits as its factorization.

123013203023537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 68040, while the sum is 35.

Adding to 123013203023537 its reverse (735320302310321), we get a palindrome (858333505333858).

The spelling of 123013203023537 in words is "one hundred twenty-three trillion, thirteen billion, two hundred three million, twenty-three thousand, five hundred thirty-seven".