Base | Representation |
---|---|
bin | 11011111110000101000000… |
… | …110000111011100010100111 |
3 | 121010112221200112122121101011 |
4 | 123332011000300323202213 |
5 | 112110422111143041401 |
6 | 1113343300552243051 |
7 | 34624261612161541 |
oct | 3376050060734247 |
9 | 533487615577334 |
10 | 123013244893351 |
11 | 3621769588033a |
12 | 1196895a9a0487 |
13 | 5384139ca3777 |
14 | 2253c3103c691 |
15 | e34ccba72451 |
hex | 6fe140c3b8a7 |
123013244893351 has 2 divisors, whose sum is σ = 123013244893352. Its totient is φ = 123013244893350.
The previous prime is 123013244893307. The next prime is 123013244893367. The reversal of 123013244893351 is 153398442310321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123013244893351 - 27 = 123013244893223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 123013244893295 and 123013244893304.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123013244893381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61506622446675 + 61506622446676.
It is an arithmetic number, because the mean of its divisors is an integer number (61506622446676).
Almost surely, 2123013244893351 is an apocalyptic number.
123013244893351 is a deficient number, since it is larger than the sum of its proper divisors (1).
123013244893351 is an equidigital number, since it uses as much as digits as its factorization.
123013244893351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1866240, while the sum is 49.
The spelling of 123013244893351 in words is "one hundred twenty-three trillion, thirteen billion, two hundred forty-four million, eight hundred ninety-three thousand, three hundred fifty-one".
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