Base | Representation |
---|---|
bin | 10001111001101011000… |
… | …000100110101001111001 |
3 | 11100121020200110221222201 |
4 | 101321223000212221321 |
5 | 130123324411421342 |
6 | 2341043103350201 |
7 | 154606261123321 |
oct | 21715300465171 |
9 | 4317220427881 |
10 | 1230155967097 |
11 | 434784a78552 |
12 | 17a4b48b2361 |
13 | 8c00708aa15 |
14 | 4377b572281 |
15 | 21eec371db7 |
hex | 11e6b026a79 |
1230155967097 has 2 divisors, whose sum is σ = 1230155967098. Its totient is φ = 1230155967096.
The previous prime is 1230155967013. The next prime is 1230155967101. The reversal of 1230155967097 is 7907695510321.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1134216480016 + 95939487081 = 1064996^2 + 309741^2 .
It is a cyclic number.
It is not a de Polignac number, because 1230155967097 - 223 = 1230147578489 is a prime.
It is not a weakly prime, because it can be changed into another prime (1230155967697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615077983548 + 615077983549.
It is an arithmetic number, because the mean of its divisors is an integer number (615077983549).
Almost surely, 21230155967097 is an apocalyptic number.
It is an amenable number.
1230155967097 is a deficient number, since it is larger than the sum of its proper divisors (1).
1230155967097 is an equidigital number, since it uses as much as digits as its factorization.
1230155967097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3572100, while the sum is 55.
The spelling of 1230155967097 in words is "one trillion, two hundred thirty billion, one hundred fifty-five million, nine hundred sixty-seven thousand, ninety-seven".
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