Base | Representation |
---|---|
bin | 10001111001101011000… |
… | …000100110101000100101 |
3 | 11100121020200110221212121 |
4 | 101321223000212220211 |
5 | 130123324411421023 |
6 | 2341043103345541 |
7 | 154606261123141 |
oct | 21715300465045 |
9 | 4317220427777 |
10 | 1230155967013 |
11 | 434784a78486 |
12 | 17a4b48b22b1 |
13 | 8c00708a97c |
14 | 4377b572221 |
15 | 21eec371d5d |
hex | 11e6b026a25 |
1230155967013 has 2 divisors, whose sum is σ = 1230155967014. Its totient is φ = 1230155967012.
The previous prime is 1230155966959. The next prime is 1230155967097. The reversal of 1230155967013 is 3107695510321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1195298330209 + 34857636804 = 1093297^2 + 186702^2 .
It is a cyclic number.
It is not a de Polignac number, because 1230155967013 - 217 = 1230155835941 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1230155964013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615077983506 + 615077983507.
It is an arithmetic number, because the mean of its divisors is an integer number (615077983507).
Almost surely, 21230155967013 is an apocalyptic number.
It is an amenable number.
1230155967013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1230155967013 is an equidigital number, since it uses as much as digits as its factorization.
1230155967013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 170100, while the sum is 43.
The spelling of 1230155967013 in words is "one trillion, two hundred thirty billion, one hundred fifty-five million, nine hundred sixty-seven thousand, thirteen".
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