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123021131300107 is a prime number
BaseRepresentation
bin11011111110001100010110…
…110101001011110100001011
3121010120201001011022120122021
4123332030112311023310023
5112111034234103100412
61113351043313305311
734624661213423215
oct3376142665136413
9533521034276567
10123021131300107
113621aa72512477
121196a39bb65237
135384ac5b23b41
14225437c5b75b5
15e350de0d0607
hex6fe316d4bd0b

123021131300107 has 2 divisors, whose sum is σ = 123021131300108. Its totient is φ = 123021131300106.

The previous prime is 123021131300063. The next prime is 123021131300149. The reversal of 123021131300107 is 701003131120321.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-123021131300107 is a prime.

It is a super-2 number, since 2×1230211313001072 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (123021131300407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61510565650053 + 61510565650054.

It is an arithmetic number, because the mean of its divisors is an integer number (61510565650054).

Almost surely, 2123021131300107 is an apocalyptic number.

123021131300107 is a deficient number, since it is larger than the sum of its proper divisors (1).

123021131300107 is an equidigital number, since it uses as much as digits as its factorization.

123021131300107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 123021131300107 its reverse (701003131120321), we get a palindrome (824024262420428).

The spelling of 123021131300107 in words is "one hundred twenty-three trillion, twenty-one billion, one hundred thirty-one million, three hundred thousand, one hundred seven".