Base | Representation |
---|---|
bin | 10001111001101110110… |
… | …101101000100010100111 |
3 | 11100121102011100100002221 |
4 | 101321232311220202213 |
5 | 130123442332400403 |
6 | 2341053320213211 |
7 | 154611001110466 |
oct | 21715665504247 |
9 | 4317364310087 |
10 | 1230220200103 |
11 | 43480825a784 |
12 | 17a51230a207 |
13 | 8c01748a60b |
14 | 43785cd29dd |
15 | 22002d0ddbd |
hex | 11e6ed688a7 |
1230220200103 has 2 divisors, whose sum is σ = 1230220200104. Its totient is φ = 1230220200102.
The previous prime is 1230220200059. The next prime is 1230220200149. The reversal of 1230220200103 is 3010020220321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1230220200103 - 221 = 1230218102951 is a prime.
It is a super-2 number, since 2×12302202001032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1230220200403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 615110100051 + 615110100052.
It is an arithmetic number, because the mean of its divisors is an integer number (615110100052).
Almost surely, 21230220200103 is an apocalyptic number.
1230220200103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1230220200103 is an equidigital number, since it uses as much as digits as its factorization.
1230220200103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 1230220200103 its reverse (3010020220321), we get a palindrome (4240240420424).
The spelling of 1230220200103 in words is "one trillion, two hundred thirty billion, two hundred twenty million, two hundred thousand, one hundred three".
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