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12302233130113 is a prime number
BaseRepresentation
bin1011001100000101011000…
…1111000101010010000001
31121120002012210000220011021
42303001112033011102001
53103024433140130423
642055322354545441
72406543543150313
oct263012617052201
947502183026137
1012302233130113
113a13390979883
121468308b98281
136b313207c754
143076075437b3
1516502169295d
hexb30563c5481

12302233130113 has 2 divisors, whose sum is σ = 12302233130114. Its totient is φ = 12302233130112.

The previous prime is 12302233130027. The next prime is 12302233130189. The reversal of 12302233130113 is 31103133220321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6960273362289 + 5341959767824 = 2638233^2 + 2311268^2 .

It is an emirp because it is prime and its reverse (31103133220321) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12302233130113 - 225 = 12302199575681 is a prime.

It is not a weakly prime, because it can be changed into another prime (12302233131113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151116565056 + 6151116565057.

It is an arithmetic number, because the mean of its divisors is an integer number (6151116565057).

Almost surely, 212302233130113 is an apocalyptic number.

It is an amenable number.

12302233130113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12302233130113 is an equidigital number, since it uses as much as digits as its factorization.

12302233130113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 12302233130113 its reverse (31103133220321), we get a palindrome (43405366350434).

The spelling of 12302233130113 in words is "twelve trillion, three hundred two billion, two hundred thirty-three million, one hundred thirty thousand, one hundred thirteen".