Base | Representation |
---|---|
bin | 1011001100000101101001… |
… | …0011100101101000001011 |
3 | 1121120002101112112101022221 |
4 | 2303001122103211220023 |
5 | 3103030103130420133 |
6 | 42055333234354511 |
7 | 2406545332462315 |
oct | 263013223455013 |
9 | 47502345471287 |
10 | 12302301420043 |
11 | 3a13416482038 |
12 | 1468327a2ba37 |
13 | 6b314326caab |
14 | 30761263c7b5 |
15 | 165027681a2d |
hex | b305a4e5a0b |
12302301420043 has 2 divisors, whose sum is σ = 12302301420044. Its totient is φ = 12302301420042.
The previous prime is 12302301420011. The next prime is 12302301420067. The reversal of 12302301420043 is 34002410320321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12302301420043 - 25 = 12302301420011 is a prime.
It is not a weakly prime, because it can be changed into another prime (12302301421043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151150710021 + 6151150710022.
It is an arithmetic number, because the mean of its divisors is an integer number (6151150710022).
Almost surely, 212302301420043 is an apocalyptic number.
12302301420043 is a deficient number, since it is larger than the sum of its proper divisors (1).
12302301420043 is an equidigital number, since it uses as much as digits as its factorization.
12302301420043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 12302301420043 its reverse (34002410320321), we get a palindrome (46304711740364).
The spelling of 12302301420043 in words is "twelve trillion, three hundred two billion, three hundred one million, four hundred twenty thousand, forty-three".
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