Base | Representation |
---|---|
bin | 1011001100000110000001… |
… | …1011000011010110101111 |
3 | 1121120002122200122000121012 |
4 | 2303001200123003112233 |
5 | 3103030310413240421 |
6 | 42055351342055435 |
7 | 2406551016646223 |
oct | 263014033032657 |
9 | 47502580560535 |
10 | 12302404040111 |
11 | 3a134693a3009 |
12 | 146835627a57b |
13 | 6b315b5c0023 |
14 | 307622112783 |
15 | 1650316a295b |
hex | b30606c35af |
12302404040111 has 2 divisors, whose sum is σ = 12302404040112. Its totient is φ = 12302404040110.
The previous prime is 12302404040089. The next prime is 12302404040131. The reversal of 12302404040111 is 11104040420321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12302404040111 - 222 = 12302399845807 is a prime.
It is a super-2 number, since 2×123024040401112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12302404040131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6151202020055 + 6151202020056.
It is an arithmetic number, because the mean of its divisors is an integer number (6151202020056).
Almost surely, 212302404040111 is an apocalyptic number.
12302404040111 is a deficient number, since it is larger than the sum of its proper divisors (1).
12302404040111 is an equidigital number, since it uses as much as digits as its factorization.
12302404040111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 12302404040111 its reverse (11104040420321), we get a palindrome (23406444460432).
The spelling of 12302404040111 in words is "twelve trillion, three hundred two billion, four hundred four million, forty thousand, one hundred eleven".
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