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123041343142 = 261520671571
BaseRepresentation
bin111001010010111010…
…1011110011010100110
3102202120221222211222001
41302211311132122212
54003442040440032
6132305134555514
711614036106014
oct1624565363246
9382527884861
10123041343142
11481aa6a3253
121ba1a368b9a
13b7ab3158b3
145d532318b4
153301eb43e7
hex1ca5d5e6a6

123041343142 has 4 divisors (see below), whose sum is σ = 184562014716. Its totient is φ = 61520671570.

The previous prime is 123041343127. The next prime is 123041343157. The reversal of 123041343142 is 241343140321.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (123041343127) and next prime (123041343157).

It is a self number, because there is not a number n which added to its sum of digits gives 123041343142.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30760335784 + ... + 30760335787.

It is an arithmetic number, because the mean of its divisors is an integer number (46140503679).

Almost surely, 2123041343142 is an apocalyptic number.

123041343142 is a deficient number, since it is larger than the sum of its proper divisors (61520671574).

123041343142 is an equidigital number, since it uses as much as digits as its factorization.

123041343142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61520671573.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 123041343142 its reverse (241343140321), we get a palindrome (364384483463).

The spelling of 123041343142 in words is "one hundred twenty-three billion, forty-one million, three hundred forty-three thousand, one hundred forty-two".

Divisors: 1 2 61520671571 123041343142