Base | Representation |
---|---|
bin | 11011111110100111011101… |
… | …001111111011110110011111 |
3 | 121010200111011002122221202201 |
4 | 123332213131033323312133 |
5 | 112112023332340131101 |
6 | 1113412254551432331 |
7 | 34630041260351041 |
oct | 3376473517736637 |
9 | 533614132587681 |
10 | 123050230005151 |
11 | 36231344a1a239 |
12 | 11973b610856a7 |
13 | 538778255acc7 |
14 | 225593d049a91 |
15 | e35c43a23e01 |
hex | 6fe9dd3fbd9f |
123050230005151 has 2 divisors, whose sum is σ = 123050230005152. Its totient is φ = 123050230005150.
The previous prime is 123050230005013. The next prime is 123050230005187. The reversal of 123050230005151 is 151500032050321.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 123050230005151 - 213 = 123050229996959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (123050230105151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61525115002575 + 61525115002576.
It is an arithmetic number, because the mean of its divisors is an integer number (61525115002576).
Almost surely, 2123050230005151 is an apocalyptic number.
123050230005151 is a deficient number, since it is larger than the sum of its proper divisors (1).
123050230005151 is an equidigital number, since it uses as much as digits as its factorization.
123050230005151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4500, while the sum is 28.
Adding to 123050230005151 its reverse (151500032050321), we get a palindrome (274550262055472).
The spelling of 123050230005151 in words is "one hundred twenty-three trillion, fifty billion, two hundred thirty million, five thousand, one hundred fifty-one".
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