Base | Representation |
---|---|
bin | 10110111010111001… |
… | …10100010000111111 |
3 | 1011202120111122100101 |
4 | 23131130310100333 |
5 | 200200121102224 |
6 | 5353012141531 |
7 | 613635633313 |
oct | 133534642077 |
9 | 34676448311 |
10 | 12305253439 |
11 | 5244aa4046 |
12 | 24750078a7 |
13 | 121148186b |
14 | 84a39bb43 |
15 | 4c046b044 |
hex | 2dd73443f |
12305253439 has 2 divisors, whose sum is σ = 12305253440. Its totient is φ = 12305253438.
The previous prime is 12305253431. The next prime is 12305253473. The reversal of 12305253439 is 93435250321.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12305253439 - 23 = 12305253431 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12305253398 and 12305253407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12305253431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6152626719 + 6152626720.
It is an arithmetic number, because the mean of its divisors is an integer number (6152626720).
Almost surely, 212305253439 is an apocalyptic number.
12305253439 is a deficient number, since it is larger than the sum of its proper divisors (1).
12305253439 is an equidigital number, since it uses as much as digits as its factorization.
12305253439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 37.
The spelling of 12305253439 in words is "twelve billion, three hundred five million, two hundred fifty-three thousand, four hundred thirty-nine".
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