Base | Representation |
---|---|
bin | 1011001100100011000100… |
… | …0110010100101000100100 |
3 | 1121120211210000010101120212 |
4 | 2303020301012110220210 |
5 | 3103142242200330200 |
6 | 42103121112514552 |
7 | 2410245142422212 |
oct | 263106106245044 |
9 | 47524700111525 |
10 | 12310200011300 |
11 | 3a167a9a86604 |
12 | 14699710aba58 |
13 | 6b3b01798129 |
14 | 307b61669cb2 |
15 | 16533acea035 |
hex | b3231194a24 |
12310200011300 has 18 divisors (see below), whose sum is σ = 26713134024738. Its totient is φ = 4924080004480.
The previous prime is 12310200011261. The next prime is 12310200011399. The reversal of 12310200011300 is 311000201321.
It can be written as a sum of positive squares in 3 ways, for example, as 1313004306496 + 10997195704804 = 1145864^2 + 3316202^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 61550999957 + ... + 61551000156.
Almost surely, 212310200011300 is an apocalyptic number.
12310200011300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12310200011300 is an abundant number, since it is smaller than the sum of its proper divisors (14402934013438).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12310200011300 is a wasteful number, since it uses less digits than its factorization.
12310200011300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 123102000127 (or 123102000120 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 12310200011300 its reverse (311000201321), we get a palindrome (12621200212621).
The spelling of 12310200011300 in words is "twelve trillion, three hundred ten billion, two hundred million, eleven thousand, three hundred".
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