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12310240013 is a prime number
BaseRepresentation
bin10110111011011111…
…10101101100001101
31011202220212222122022
423131233311230031
5200202410140023
65353311055525
7614026212401
oct133557655415
934686788568
1012310240013
11524789a585
1224768115a5
1312125094b6
1484acd9101
154c0b037c8
hex2ddbf5b0d

12310240013 has 2 divisors, whose sum is σ = 12310240014. Its totient is φ = 12310240012.

The previous prime is 12310240009. The next prime is 12310240051. The reversal of 12310240013 is 31004201321.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6986786569 + 5323453444 = 83587^2 + 72962^2 .

It is a cyclic number.

It is not a de Polignac number, because 12310240013 - 22 = 12310240009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12310239973 and 12310240000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12310240513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155120006 + 6155120007.

It is an arithmetic number, because the mean of its divisors is an integer number (6155120007).

Almost surely, 212310240013 is an apocalyptic number.

It is an amenable number.

12310240013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12310240013 is an equidigital number, since it uses as much as digits as its factorization.

12310240013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 12310240013 its reverse (31004201321), we get a palindrome (43314441334).

The spelling of 12310240013 in words is "twelve billion, three hundred ten million, two hundred forty thousand, thirteen".