Base | Representation |
---|---|
bin | 10110111011100101… |
… | …10110110011010001 |
3 | 1011202222101011122212 |
4 | 23131302312303101 |
5 | 200203110442433 |
6 | 5353340041505 |
7 | 614036015432 |
oct | 133562666321 |
9 | 34688334585 |
10 | 12311030993 |
11 | 524828a888 |
12 | 2476b33295 |
13 | 1212725531 |
14 | 84b063489 |
15 | 4c0c0cd48 |
hex | 2ddcb6cd1 |
12311030993 has 2 divisors, whose sum is σ = 12311030994. Its totient is φ = 12311030992.
The previous prime is 12311030951. The next prime is 12311031043. The reversal of 12311030993 is 39903011321.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11468696464 + 842334529 = 107092^2 + 29023^2 .
It is an emirp because it is prime and its reverse (39903011321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12311030993 - 26 = 12311030929 is a prime.
It is a super-2 number, since 2×123110309932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12311030933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6155515496 + 6155515497.
It is an arithmetic number, because the mean of its divisors is an integer number (6155515497).
Almost surely, 212311030993 is an apocalyptic number.
It is an amenable number.
12311030993 is a deficient number, since it is larger than the sum of its proper divisors (1).
12311030993 is an equidigital number, since it uses as much as digits as its factorization.
12311030993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374, while the sum is 32.
The spelling of 12311030993 in words is "twelve billion, three hundred eleven million, thirty thousand, nine hundred ninety-three".
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