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123112104013 is a prime number
BaseRepresentation
bin111001010101000001…
…1011010000001001101
3102202202220010212122001
41302222003122001031
54004113144312023
6132320143352301
711615555421643
oct1625203320115
9382686125561
10123112104013
1148236633a08
121ba39bb2691
13b7bcb8c832
145d5c7b1193
1533082e06ad
hex1caa0da04d

123112104013 has 2 divisors, whose sum is σ = 123112104014. Its totient is φ = 123112104012.

The previous prime is 123112104001. The next prime is 123112104019. The reversal of 123112104013 is 310401211321.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65126019204 + 57986084809 = 255198^2 + 240803^2 .

It is a cyclic number.

It is not a de Polignac number, because 123112104013 - 25 = 123112103981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (123112104019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61556052006 + 61556052007.

It is an arithmetic number, because the mean of its divisors is an integer number (61556052007).

Almost surely, 2123112104013 is an apocalyptic number.

It is an amenable number.

123112104013 is a deficient number, since it is larger than the sum of its proper divisors (1).

123112104013 is an equidigital number, since it uses as much as digits as its factorization.

123112104013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 123112104013 its reverse (310401211321), we get a palindrome (433513315334).

The spelling of 123112104013 in words is "one hundred twenty-three billion, one hundred twelve million, one hundred four thousand, thirteen".